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Array of array products - February 25, 2018 - dynamic programming method
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using System; | |
class Solution | |
{ | |
public static int[] ArrayOfArrayProducts(int[] arr) | |
{ | |
if(arr == null || arr.Length <= 1) | |
{ | |
return new int[0]; | |
} | |
int length = arr.Length; | |
int leftProduct = 1; | |
var product = new int[length]; | |
for(int i = 0; i < length; i++) | |
{ | |
product[i] = leftProduct; | |
leftProduct *= arr[i]; | |
} | |
int rightProduct = 1; | |
for(int i = length - 1; i >= 0; i--) | |
{ | |
product[i] *= rightProduct; | |
rightProduct *= arr[i]; | |
} | |
return product; | |
} | |
static void Main(string[] args) | |
{ | |
var product = ArrayOfArrayProducts(new int[]{8, 10, 2}); | |
foreach(var item in product) | |
{ | |
Console.WriteLine(item); | |
} | |
} | |
} | |
/* | |
Keyword: integer array, | |
ask: product of all integers except itself on the index | |
dynamic programming | |
[8, 10, 2] | |
-----------> | |
one multiplication | |
value = 1, value = 8 | |
product = new int[] {1, value*8, value * 10} -> 2 multiplication | |
<--------------------- | |
each time I will two mutliplication | |
product[i] = product[i] * arr[i + 1] - wrong | |
product[i] = product[i] * rightProduct - correct | |
[1, 8, 80] | |
rightProduct = 1, | |
rightProduct *= arr[i + 1] | |
[1 * 20 , 8 * 2, 80 * 1] | |
time complexity: O(n) | |
space complexity: O(n) | |
*/ |
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