1089 3 digit number math trick in python

1089_3_digit_numbers_math_trick.py

#!/usr/bin/env python

'''
Note:
	must be three digit numbers.
	no digits can repeat (so no 989, 889, etc.)
'''
import sys

def main(argv):
	for i in range(100,999):
		first_dig = int(str(i)[0])
		second_dig = int(str(i)[1])
		third_dig = int(str(i)[2])

		if first_dig != second_dig and second_dig != third_dig and first_dig != third_dig:
			x = abs(i - int(str(i)[::-1]))

			z = int(str(x)[::-1])
			if z < 100:
				z = int(str(z) + '0')

			y = x+z

			print("i: " + str(i))
			print("x: " + str(x))
			print("z: " + str(z))
			print("y: " + str(y))
			print()


if __name__ == "__main__":
	main(sys.argv)