juandesant

#!/usr/bin/env python

import datetime as dt

def riddle_for_date(date, solutions=False):
    """
    Determines the number for the Saturday Mac Riddle associated with
    a given date, considering whether it is the date for the riddle 
    or the solutions.

juandesant

\documentclass{article}
\usepackage{hyperref}
\usepackage{makeidx}
\usepackage{glossaries}

\makeindex

\makeglossaries

% Define your acronym

juandesant

# This script assumes that [mdbtools][1] are installed, for instance with
# `brew install mdbtools`
# [1]: https://github.com/mdbtools/mdbtools
# It also assumes that [pandas][2] and [pandas_access][3] are installed,
# [2]: https://pandas.pydata.org/
# [3]: https://pypi.org/project/pandas_access/
# which you can do with 
# `pip install pandas pandas_access`
# or
# `pip install pandas_access`

juandesant

digraph pictionary_play {
  node [fontname = "Handlee"];
  edge [fontname = "Handlee"];

  splines=false;

  randir=LR;
  
  draw [
    label = "Draw a picture";

juandesant

import sys
import os
from atlassian import Confluence

def obtain_confluence_pat(path='~/.ConfluencePAT'):
    confluence_PAT_filename = os.path.expanduser(path)
    confluence_PAT = None
    if os.path.exists(confluence_PAT_filename):
        with open(confluence_PAT_filename, "r") as pat_file:
            confluence_PAT = pat_file.readline()

juandesant

//Quick inverse square root using bit patterns
//Might be slower nowadays than using specific functions

// The following is the abridged version of the Quake function
// See more at https://en.wikipedia.org/wiki/Fast_inverse_square_root

//float Q_rsqrt( float number )
//{
//    long i;
//    float x2, y;

juandesant

import ads
import pandas as pd

ads.config.token='putYourOwnAdsConfigTokenHere'

bibgroups = [
    "ALMA", 
    "CfA",
    "CFHT",
    "Chandra",

juandesant

right_of(X, Y) :- X =:= Y+1.
left_of(X, Y)  :- right_of(Y, X).

next_to(X, Y)  :- right_of(X, Y).
next_to(X, Y)  :- left_of(X, Y).

solution(Street) :-
   /* There are 5 houses in the street, all of different colours; 
      and their owners all have different nationalities, smoke different brands,
      have different pets, and have different drinks */

juandesant

right_of(X, Y) :- X is Y+1.
left_of(X, Y) :- right_of(Y, X).

next_to(X, Y) :- right_of(X, Y).
next_to(X, Y) :- left_of(X, Y).

solution(Street, FishOwner) :-
    Street = [
           house(1, Nationality1,  Color1,     Pet1,   Drinks1,    Smokes1),
           house(2, Nationality2,  Color2,     Pet2,   Drinks2,    Smokes2),

juandesant

-- Based on an answer in StackOverflow
-- Q: https://stackoverflow.com/questions/18062494/how-to-enumerate-the-keys-and-values-of-a-record-in-applescript
-- A: https://stackoverflow.com/a/29545930/919692

use framework "Foundation"
set testRecord to {b:"bbb", c:"ccc", |0|:"zero", a:"aaa", |null|:"null"}

set objCDictionary to current application's NSDictionary's dictionaryWithDictionary:testRecord
set allKeys to objCDictionary's allKeys()