kanekomasahiro/extract_name_from_path.sh

Created April 21, 2021 04:00

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shellスクリプトでpathからデータとファイル形式を除去してfile名だけを抽出する．

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extract_name_from_path.sh

	# file_path=../data/hoge.bin
	# file_name=hoge

	file_name=$( echo $file_path \| cut -d/ -f4 \| sed -r 's/(.[^.]+){1}$//g')

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