binary_search.rb

def binary_search(target, list)
  position = (list.count / 2).floor
  mid = list[position]

  return mid if mid == target

  if(mid < target)
    return binary_search(target, list.slice(position + 1, list.count/2))
  else
    return binary_search(target, list.slice(0, list.count/2))
  end
end


puts binary_search(9, [1,2,3,4,5,6,7,8,9,10])

Here is a recursive implementation of binary search which is based on divide and conquer