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using namespace std; | |
typedef long long int lint; | |
typedef pair<int, lint> pil; | |
typedef pair<lint, int> pli; | |
typedef pair<lint, lint> pll; | |
const int N = 100100; | |
int n; | |
vector<pil> edges[N]; | |
pll add(pll a, pll b) { | |
if (a.first != b.first) return min(a,b); | |
return pll(a.first,(a.second+b.second)%mod); | |
} | |
pll mul(pll a,pll b){ | |
return pll(a.first+b.first,a.second*b.second%mod); | |
} | |
/* | |
* edges に辺の情報(終点、距離)を入れると、(sからの最短距離,最短距離の道の本数%mod)を保持する vector を返す。 | |
*/ | |
vector<pll> calc(int s) { | |
vector<pll> dp(n, pll(inf, 0)); | |
vector<bool> vis(n, false); | |
priority_queue<pli, vector<pli> , greater<pli> > que; | |
dp[s] = pll(0, 1); | |
que.push(pli(0, s)); | |
while (not que.empty()) { | |
pli vd = que.top(); que.pop(); | |
int v = vd.second; | |
if (vis[v]) continue; | |
vis[v] = true; | |
REP(i, 0, edges[v].size()) { | |
pil wc = edges[v][i]; | |
int w = wc.first; | |
lint c = wc.second; | |
dp[w]=add(dp[w],mul(dp[v],pll(c,1))); | |
que.push(pli(dp[w].first,w)); | |
} | |
} | |
return dp; | |
} |
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