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Use Python to send and receive emails

Use Python to:

  • send a plain text email
  • send an email with attachment
  • receive and filter emails according to some criteria
import smtplib
from email.mime.text import MIMEText
smtp_ssl_host = 'smtp.gmail.com' # smtp.mail.yahoo.com
smtp_ssl_port = 465
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'
sender = 'ME@EXAMPLE.COM'
targets = ['HE@EXAMPLE.COM', 'SHE@EXAMPLE.COM']
msg = MIMEText('Hi, how are you today?')
msg['Subject'] = 'Hello'
msg['From'] = sender
msg['To'] = ', '.join(targets)
server = smtplib.SMTP_SSL(smtp_ssl_host, smtp_ssl_port)
server.login(username, password)
server.sendmail(sender, targets, msg.as_string())
server.quit()
import os
import smtplib
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
smtp_ssl_host = 'smtp.gmail.com' # smtp.mail.yahoo.com
smtp_ssl_port = 465
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'
sender = 'ME@EXAMPLE.COM'
targets = ['HE@EXAMPLE.COM', 'SHE@EXAMPLE.COM']
msg = MIMEMultipart()
msg['Subject'] = 'I have a picture'
msg['From'] = sender
msg['To'] = ', '.join(targets)
txt = MIMEText('I just bought a new camera.')
msg.attach(txt)
filepath = '/path/to/image/file'
with open(filepath, 'rb') as f:
img = MIMEImage(f.read())
img.add_header('Content-Disposition',
'attachment',
filename=os.path.basename(filepath))
msg.attach(img)
server = smtplib.SMTP_SSL(smtp_ssl_host, smtp_ssl_port)
server.login(username, password)
server.sendmail(sender, targets, msg.as_string())
server.quit()
import time
from itertools import chain
import email
import imaplib
imap_ssl_host = 'imap.gmail.com' # imap.mail.yahoo.com
imap_ssl_port = 993
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'
# Restrict mail search. Be very specific.
# Machine should be very selective to receive messages.
criteria = {
'FROM': 'PRIVILEGED EMAIL ADDRESS',
'SUBJECT': 'SPECIAL SUBJECT LINE',
'BODY': 'SECRET SIGNATURE',
}
uid_max = 0
def search_string(uid_max, criteria):
c = list(map(lambda t: (t[0], '"'+str(t[1])+'"'), criteria.items())) + [('UID', '%d:*' % (uid_max+1))]
return '(%s)' % ' '.join(chain(*c))
# Produce search string in IMAP format:
# e.g. (FROM "me@gmail.com" SUBJECT "abcde" BODY "123456789" UID 9999:*)
def get_first_text_block(msg):
type = msg.get_content_maintype()
if type == 'multipart':
for part in msg.get_payload():
if part.get_content_maintype() == 'text':
return part.get_payload()
elif type == 'text':
return msg.get_payload()
server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
server.login(username, password)
server.select('INBOX')
result, data = server.uid('search', None, search_string(uid_max, criteria))
uids = [int(s) for s in data[0].split()]
if uids:
uid_max = max(uids)
# Initialize `uid_max`. Any UID less than or equal to `uid_max` will be ignored subsequently.
server.logout()
# Keep checking messages ...
# I don't like using IDLE because Yahoo does not support it.
while 1:
# Have to login/logout each time because that's the only way to get fresh results.
server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
server.login(username, password)
server.select('INBOX')
result, data = server.uid('search', None, search_string(uid_max, criteria))
uids = [int(s) for s in data[0].split()]
for uid in uids:
# Have to check again because Gmail sometimes does not obey UID criterion.
if uid > uid_max:
result, data = server.uid('fetch', uid, '(RFC822)') # fetch entire message
msg = email.message_from_string(data[0][1])
uid_max = uid
text = get_first_text_block(msg)
print 'New message :::::::::::::::::::::'
print text
server.logout()
time.sleep(1)
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