milo0

Keybase proof

I hereby claim:

• I am milo0 on github.
• I am milo0 (https://keybase.io/milo0) on keybase.
• I have a public key ASAqn1wF5KMGkvNvjpY9IlULdDb0H4ucexTqCLm6Jlkvrwo

To claim this, I am signing this object:

milo0

import pandas as pd

with open('table.txt') as f:
    content = f.readlines()
    
columns = content.pop(0)
content_list = [row.split() for row in content]

df = pd.DataFrame(columns=columns, data=content_list)

milo0

def concatenate_per_row(A, B):
    m1,n1 = A.shape
    m2,n2 = B.shape

    out = np.zeros((m1, m2, n1+n2), dtype=A.dtype)
    out[:, :, :n1] = A[:, None, :]
    out[:, :, n1:] = B

    return out.reshape(m1*m2, -1)

milo0

import itertools, sys
from time import sleep

spinner = itertools.cycle(['|', '/', '-', '\\'])
while True:
    sys.stdout.write(next(spinner))  # write the next character
    sys.stdout.flush()                # flush stdout buffer (actual character display)
    sys.stdout.write('\b')            # erase the last written char
    sleep(0.1)

milo0

def merge_dfs(df1, df2):
    """Merge two DataFrames. Common columns among the dfs are reduced to one."""
    res = pd.merge(df1, df2, how='outer', left_index=True, right_index=True)
    cols = sorted(res.columns)
    pairs = []
    for col1, col2 in zip(cols[:-1], cols[1:]):
        if col1.endswith('_x') and col2.endswith('_y'):
            pairs.append((col1, col2))
    for col1, col2 in pairs:
        res[col1[:-2]] = res[col1].combine_first(res[col2])

milo0

def extract_integers(string):
    extracted_ints = [int(s) for s in string.split() if s.isdigit()]

    return extracted_ints

def extract_floats(string):
    floats = []
    for s in string.split():
        try:
            extracted_floats.append(float(s))