Download image from url and save as file

download_image.py

import io

from PIL import Image  # https://pillow.readthedocs.io/en/4.3.x/
import requests  # http://docs.python-requests.org/en/master/


# example image url: https://m.media-amazon.com/images/S/aplus-media/vc/6a9569ab-cb8e-46d9-8aea-a7022e58c74a.jpg
def download_image(url, image_file_path):
    r = requests.get(url, timeout=4.0)
    if r.status_code != requests.codes.ok:
        assert False, 'Status code error: {}.'.format(r.status_code)

    with Image.open(io.BytesIO(r.content)) as im:
        im.save(image_file_path)

    print('Image downloaded from url: {} and saved to: {}.'.format(url, image_file_path))

Just perfect, thanks! It was strange to find that such a common task is not solved on first link in google.
A one-liner version: PIL.Image.open(io.BytesIO(request.urlopen(url).read())).save(image_file_path)

Thank you so much for sharing the code. It helps me a lot.

Perfect! The only one that works 100%
Thank you

how to use it can anyone explain?

https://yt3.googleusercontent.com/m6BZSdqN3qUiThNGeig8Vkrbeu4CQJpwE0fy5lzIPU4jtyRd2nE70O-wy8X2dRAanSVNDWbe=s176-c-k-c0x00ffffff-no-rj