no1xsyzy

import re
PATTERN = r"/|(/[^.][^/]*|/[^/][^./][^/]*|/\.\.[^/]+)+/?"

assert re.fullmatch(PATTERN, "/abc/") is not None
assert re.fullmatch(PATTERN, "/abc/../") is None
assert re.fullmatch(PATTERN, "/abc/./") is None
assert re.fullmatch(PATTERN, "/abc/.123/") is not None
assert re.fullmatch(PATTERN, "/abc/a.123/") is not None
assert re.fullmatch(PATTERN, "/abc/a./") is not None

no1xsyzy

#lang racket
(define (cup volume)
  (define amount 0)
  (define (pour-in! d)
    (let ([old-amount amount])
      (if (> (+ old-amount d) volume)
          (begin
            (set! amount volume)
            (- (+ old-amount d) volume))
          (begin

no1xsyzy

# coding:utf-8
import requests
import threading
from queue import Queue, Empty
import time
c_thrd = int(input("请输入要执行的线程数："))
# 设置队列长度
workQueue = Queue(c_thrd)
# 线程池
threads = []

no1xsyzy

#lang racket
;;; Solve <https://www.v2ex.com/t/619370>

(define (get-group ipaddr lines)
  (define group-name null)
  (let/cc return
    (map (λ (line)
           (cond
             [(parse-group-name line)
              => (λ (parsed-group-name)

no1xsyzy

def deleteorder(x):
    n = len(x)
    if n%2 != 0:
        return
    if any(x.count(i) > n//2 for i in set(x)):
        return
    x = sorted(x)
    assert all(x[i] < x[i + n//2] for i in range(n//2))
    # since x[0] <= x[1] <= x[2] <= ... <= x[n-1]
    # there must be x[i] <= x[i + n//2]

no1xsyzy

from mitmproxy import http

def request(flow: http.HTTPFlow) -> None:
    if 'magicnumber' in flow.request.query:
        print(repr(flow.request.query['magicnumber']))
        flow.response = flow.response = http.HTTPResponse.make(200)

def response(flow: http.HTTPFlow) -> None:
    flow.response.content = flow.response.content.replace(
        b"</body>",

no1xsyzy

import itertools, functools, operator
from typing import *
class Solution:
    def singleNumber(self, lst: List[int], k: int) -> int:
        pattern = []
        for i in itertools.count():
            if k & 1 != 0:
                pattern.append(i)
            k >>= 1
            if k == 0:

no1xsyzy

#lang racket
(define (remove-palindrome s)
  (define f
    (cachedproc
     (lambda (i j)
       (cond
         [(equal? i j) 1]
         [(equal? (+ i 1) j) 1]
         ;[(and (equal? (+ i 2) j) (equal? (list-ref s i) (list-ref s (- j 1)))) 1]
         [(equal? (list-ref s i) (list-ref s (- j 1))) (f (+ i 1) (- j 1))]

no1xsyzy

((m=>`${m.replace(/([?&])name=[^&]+/, "$1name=orig")} --out=twitter${(x=>x[x.length-1])(window.location.pathname.split("/"))}.${/[&?]format=([^&]+)&/.exec(m)[1]}`)(document.querySelector(`div[data-testid="primaryColumn"] img[src^="https://pbs.twimg.com/media"]`).src))

((ms,f)=>ms.map(f(ms.length>1)).join("\n"))(Array.from(document.querySelectorAll(`div[data-testid="primaryColumn"] img[src^="https://pbs.twimg.com/media"]`)).map(x=>x.src), (l=>{var c=0;return m=>`${m.replace(/([?&])name=[^&]+/, "$1name=orig")} --out=twitter${(x=>x[x.length-1])(window.location.pathname.split("/"))}${l?"-"+("0"+(++c)).slice(-2,100):""}.${/[&?]format=([^&]+)&/.exec(m)[1]}`}))

no1xsyzy

The project hugetiny/negibox is abusing FOSS projects

The following is a backup of https://github.com/hugetiny/negibox/issues/6 in case deleted.

Using aria2/aria2 without satifying GPLv2 or later version

You stated that this is based on https://github.com/aria2/aria2, I suppose Negiboxc.exe is actually aria2c.exe. --version option also supports that. Is there any changes and if yes what are they? Where's your source code and license? You haven't even forked aria2. GPLv2 does require extra efforts if you want to put it into your project. GPLv3 even requires more permissions.

Using mayswind/AriaNg without satisfying MIT license