| import java.util.*; | |
| public class Predtech { | |
| public static void main(String[] args) { | |
| Scanner sc = new Scanner(System.in); | |
| int n = sc.nextInt(); | |
| String[] s = new String[n + 2]; | |
| for (int i = 0; i < n + 1; i++) { | |
| s[i] = sc.nextLine(); | |
| } |
| #!/bin/life | |
| # coding: utf-8 | |
| class Olympiad: | |
| def __init__(self, subject): | |
| pass | |
| def makeRound(self, level): | |
| return Round(self, level) |
| #!/bin/bash | |
| if [ "`whoami`" != "root" ]; then | |
| echo "Please run this script as root" | |
| else | |
| echo "Going to install latest stable Firefox, is it OK?" | |
| echo "Press Enter to continue or Ctrl-C to stop" | |
| if read; then | |
| echo "Adding Linux Mint repo..." |
| var tablerow = $('<tr><td>' + person.id + '</td><td>' + person.name + '</td><td>' + person.school + '</td><td>' + person.class + tasksMass + person.total + '</td></tr>'); |
| <?xml version="1.0" encoding="UTF-8"?> | |
| <openbox_config xmlns="http://openbox.org/3.4/rc" xmlns:xi="http://www.w3.org/2001/XInclude"> | |
| <resistance> | |
| <strength>10</strength> | |
| <screen_edge_strength>20</screen_edge_strength> | |
| </resistance> | |
| <focus> | |
| <focusNew>yes</focusNew> | |
| <followMouse>no</followMouse> | |
| <focusLast>yes</focusLast> |
| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta charset="utf-8" /> | |
| </head> | |
| <body> | |
| <script id="worker1" type="javascript/worker"> | |
| /*! | |
| * A crc32 function that will produce the same result as PHP's crc32() function | |
| * (http://php.net/crc32). |
| var ajax = new XMLHttpRequest(); | |
| ajax.onreadystatechange = function(){ | |
| if(ajax.readyState == 4) { | |
| // the request have successfully finished | |
| alert(ajax.responseText); | |
| } | |
| } | |
| ajax.open("GET", "hello.txt", true); |
% Экскаватор. Формула Тейлора
Нулевой производной многочлена будем называть сам многочлен. Тогда для любого $P_n(x, x_0)$:
$P_n(x, x_0) = c_0 + c_1 (x - x_0) + c_2 (x - x_0) ^ 2 + c_3 (x - x_0) ^ 3 + \cdots + c_n (x - x_0) ^ n$, где $c_k = P^{(k)}(x_0)$.
Доказательство. Рассмотрим $P'(x)$:
| { | |
| "title": "Прадам айфун 5", | |
| "text": "айфон 5 продам бесплатно без смс", | |
| "seller": { | |
| "id": 1488228, | |
| "name": "Ашот" | |
| }, | |
| "photo": "http://i.imgur.com/YusLYky.jpg" | |
| } |
