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February 1, 2025 15:58
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4o-aquarium
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<USER> | |
### 2. Aquarium | |
In the aquarium, there are octopuses with eight arms and starfish with five arms. | |
**How many starfish are there in the aquarium if the total number of arms of all the animals living in it is 41?** | |
<ASSISTANT> | |
Let's solve this step by step. | |
### Step 1: Define Variables | |
- Let **x** = number of octopuses | |
- Let **y** = number of starfish | |
### Step 2: Set Up the Equation | |
Each octopus has 8 arms, and each starfish has 5 arms. The total number of arms is 41. So, the equation becomes: | |
\[ | |
8x + 5y = 41 | |
\] | |
### Step 3: Find Integer Solutions | |
Since the number of animals can't be negative or fractional, we look for **non-negative integer solutions**. | |
We'll test different values of **x**: | |
- **If \( x = 0 \):** \( 5y = 41 \) → \( y = 8.2 \) (not an integer) | |
- **If \( x = 1 \):** \( 8 + 5y = 41 \) → \( 5y = 33 \) → \( y = 6.6 \) (not an integer) | |
- **If \( x = 2 \):** \( 16 + 5y = 41 \) → \( 5y = 25 \) → \( y = 5 \) ✅ (integer solution) | |
- **If \( x = 3 \):** \( 24 + 5y = 41 \) → \( 5y = 17 \) → \( y = 3.4 \) (not an integer) | |
- **If \( x = 4 \):** \( 32 + 5y = 41 \) → \( 5y = 9 \) → \( y = 1.8 \) (not an integer) | |
- **If \( x = 5 \):** \( 40 + 5y = 41 \) → \( 5y = 1 \) → \( y = 0.2 \) (not an integer) | |
No other positive integer solutions exist. | |
### ✅ Final Answer: | |
The aquarium has **5 starfish**. |
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