Created
November 7, 2018 10:48
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The famous Josephus problem
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# There are n men numbered 1 through n standing in a circle. Starting | |
# from the first, every m-th man is killed, continuing the process | |
# from the next man in the circle. Who is the last to be killed? | |
# recursive | |
def l(n, m): | |
if n == 1: return 0 | |
f = (m-1) % n | |
k = l(n-1, m) | |
if k <= n-1-(f+1): return k+f+1 | |
return k-(n-f-1) | |
def L(n, m): return 1 + l(n, m) | |
# iterative | |
def l0(N, m): | |
k = 0 | |
for n in range(2, N+1): | |
f = (m-1) % n | |
k = k+f+1 if k <= n-1-(f+1) else k-(n-f-1) | |
return k | |
def L0(n, m): return 1 + l0(n, m) | |
n, m = 10**6, 2 | |
print(L0(n, m)) |
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