raheemazeezabiodun

"""
This demonstrates how to use singledispatch for dispatching on type

We want to draw each based on the type. Typically, we can use if else statement to check the type
then call the function that does draw the shape, however, we will keep having multiple if elif statement.

This is just another pythonic way of doing it
"""

from functools import singledispatch

raheemazeezabiodun

def slow_gcd(arg1,arg2):
    gcd = 0
    for num in range(1, arg1 + arg2+ 1):
        if (arg1 % num == 0) and (arg2 %num == 0):
            gcd = num
    return gcd


def fast_gcd(arg1,arg2):
    if arg2 == 0:

raheemazeezabiodun

def slow_fibonacci_number(n):
    if n <= 1:
        return n
    return slow_fibonacci_number(n - 1) + slow_fibonacci_number(n - 2)


def fast_fibonacci_number(n):
    numbers = [0, 1]
    for num in range(2, n+1):
        numbers.append(numbers[num - 1] + numbers[num - 2])

raheemazeezabiodun

"""
The try block tries to execute an expression

If an error occurs, it calls the except block alone
If no error occur, it calls the else block

The idea behind this is, if the school exists, print it out
"""

schools = {

raheemazeezabiodun

/*
different ways of looping through a vector in c++
*/

#include <iostream>
#include <vector>
#include <numeric> // for style_four

using std::cout;
using std::vector;