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Ackermann–Péter function, with and without recursion. Faster without!
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// "Canonical", recursive | |
const ap = (m, n) => { | |
if (m === 0) return n + 1; | |
if (m > 0 && n === 0) return ap(m - 1, 1); | |
if (m > 0 && n > 0) return ap(m - 1, ap(m, n - 1)); | |
}; | |
// Non-recursive. Faster, and won't exceed call stack size! | |
// But maybe the array will get too huge. | |
const ap2 = (m, n) => { | |
let cm = []; | |
while (true) { | |
if (m === 0) { | |
if (!cm.length) return n + 1; | |
m = cm.pop(); | |
++n; | |
} else if (m > 0 && n === 0) { | |
--m; | |
n = 1; | |
} else if (m > 0 && n > 0) { | |
--n; | |
cm.push(m - 1); | |
} | |
} | |
}; | |
// minified, golfed | |
a=(m,n)=>m?n?a(m-1,a(m,--n)):a(--m,1):++n | |
// It can go smaller: | |
// https://codegolf.stackexchange.com/questions/40141/the-ackermann-function | |
// non-recursive minified (WIP) | |
ax=(m,n)=>{ | |
for(cm=[];m+cm.length;){ | |
m?n?(cm.push(m-1),--n):n=(--m,1):m=cm.pop(++n) | |
} | |
return ++n | |
} | |
module.exports.ap = ap; | |
module.exports.ap2 = ap2; | |
module.exports.ap3 = ap3; | |
module.exports.a = a; | |
module.exports.ax = ax; |
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