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# SQL Injection Password BruteForce for CTF Challenge | |
# By Hycodex | |
import requests | |
import string | |
# Payload Injection | |
payload = "'or+1=1 AND password LIKE '{0}%'#" |
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### Keybase proof | |
I hereby claim: | |
* I am sauloh on github. | |
* I am sauloh (https://keybase.io/sauloh) on keybase. | |
* I have a public key ASACRFPzVvBybzWpk5goJwO_FG7kiokcRuNBRZgkoO_mWQo | |
To claim this, I am signing this object: |
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int sum(int num) | |
if num is 1: | |
return 1 | |
else | |
return num + sum(num - 1) |
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#!/usr/bin/env python | |
"""Simple HTTP Server With Upload. | |
This module builds on BaseHTTPServer by implementing the standard GET | |
and HEAD requests in a fairly straightforward manner. | |
""" |
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#include<stdio.h> | |
int main() | |
{ | |
int sum; | |
int counter; | |
int rest; | |
sum = 0; | |
counter = 0; |
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a = 0; | |
for(k=0, k <= 10, k++) | |
a = a + k; |
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a = 0 | |
while (a != 1) | |
{ | |
print a | |
a = input_from_user() | |
} |
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if a > b: | |
a is bigger | |
else if: | |
b is bigger |
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d = a + b // sum two variables a and b and stores the result in d | |
d = a - c // subtract ‘c’ from ‘a’ and stores the result in d | |
d = a / c </b> // divide a by c and stores the result in d | |
d =a % c </b> // divide a by c and stores the result in d |
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int sum(int a, int b) | |
{ | |
int c; | |
c = a + b; | |
return c; | |
} | |
sum(value1, value2); |
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