largen number truncator

truncator.py

#!/usr/bin/env python                                                            
                                                                                 
def humanize_wordcount(value, lower_bound=10**3, upper_bound=10**12):            
    """                                                                          
    Similar to humanize's intword. Converts a large integer to a friendly text   
    representation. For example, 1000 becomes '1K', 1000000 becomes '1M' etc.    
    """                                                                          
    try:                                                                         
        value = int(value)                                                       
    except (TypeError, ValueError):                                              
        return value                                                             
                                                                                 
    if value <= lower_bound or value >= upper_bound:                             
        return value                                                             
                                                                                 
    scaling_factor, symbol = (10**3, 'K') if value < 10**6 else  \               
                             (10**6, 'M') if value < 10**9 else  \               
                             (10**9, 'B')                                        
                                                                                 
    new_value = value / float(scaling_factor)                                    
    precision = 0 if int(new_value) >= 100 else 1                                
    return '%.*f%s' % (precision, new_value, symbol)  

Should remove bound arguments (and hardcode the values, so as to make sure everything words as intended).