specbug

import hashlib
import binascii
import random

def derive_key(password, salt, iterations, dklen):
    password = password.encode('utf-8')
    salt = salt.encode('utf-8')
    dk = hashlib.pbkdf2_hmac('sha256', password, salt, iterations, dklen)
    return binascii.hexlify(dk).decode('utf-8')

specbug

"""

Run: `python ia_assignment.py 5`

(1) Generate all combinations & prune branches with four consecutive misses. 
(2) Track cases where the student is absent on the Nth day.

I use backtracking to generate all combinations with early pruning to optimize runtime. 
For each valid attendance branch, we increment the count of ways by one. 
If a branch concludes with an absence, the count of misses increases by one.

specbug

#!/bin/zsh

if [[ "$1" == "work" ]]; then
    git config --global user.email <work email>
    git config --global user.name <work username>
    echo "Switched to work profile"
elif [[ "$1" == "personal" ]]; then
    git config --global user.email <personal email>
    git config --global user.name <personal username>
    echo "Switched to personal profile"

specbug

Keybase proof

I hereby claim:

• I am specbug on github.
• I am specbug (https://keybase.io/specbug) on keybase.
• I have a public key ASDStgoHWKiP216MqojMY0BmVc9Ybb1q2-PoQ--w5FYOXwo

To claim this, I am signing this object:

specbug

# Analyze the clusters and connections in the graph
for node, cluster in partition.items():
  if cluster == 1:
    # Calculate the percentage of nodes that represent Tweets and the percentage of nodes that represent people you follow
    num_tweets = len([n for n in cluster1 if n['type'] == 'tweet'])
    num_following = len([n for n in cluster1 if n['type'] == 'person'])
    tweet_percentage = num_tweets / len(cluster1)
    following_percentage = num_following / len(cluster1)
    print(f'Cluster 1: {tweet_percentage}% Tweets, {following_percentage}% people you follow')

specbug

specbug

#1

for i in range(n): # executes n times - {1}
	for j in range(m): # executes m times - {2}
		t += i * j # executes in constant time - {3}

specbug

def curry(func):
	total_args = func.__code__.co_argcount
	def curried_wrapper(*args):
		l_args = list(args)

		def recurry(*args):
			l_args.extend(args)
			if len(l_args) == total_args:
				return func(*l_args)
			return recurry

specbug

# Place all repos, and the script, in a folder.

COUNTER=0

for d in */
do
	cd "./$d"
	GIT_C=$(git rev-list --all --count)
	echo "Commits in $d: $GIT_C"
	COUNTER=$((COUNTER + GIT_C))