# Spencer Tippingspencertipping

View metal-chess-set.md

# A questionably-manufactured metal chess set

It started when Joyce was going to buy a chess set from Amazon. There's nothing wrong with the chess sets there, but they're made of plastic and aren't very interesting. So I offered to make one out of metal instead. Here's what I ended up with:

View gist:1219204
 # This example was run in IRB 1.9.2 p290. # Initialize x, y, z, and t to some values using a parallel assignment: > x, y, z, t = 1, 2, 3, 4 => [1, 2, 3, 4] # In the case above, '=' has lower precedence than ',', so there's a 4-ary # lvalue and a 4-element rvalue. > x, y = z, t = 1, 2
View gist:1014640
 it.encode85(s) = encoded -where [encode_block(n) = n[5] *[String.fromCharCode(33 + n / powers_of_85[4 - x] % 85)] -seq -re- it.join(''), padded = s.length & 1 ? s + String.fromCharCode(0) : s, encoded_string = n[0, padded.length, 2] *[encode_block((padded.charCodeAt(x) << 16) >>> 0 | padded.charCodeAt(x + 1))] -seq -re- it.join(''), encoded = s.length & 1 ? encoded_string.substr(0, encoded_string.length - 2) : encoded_string], it.decode85(s) = decoded -where [decode_block(n) = String.fromCharCode(n >>> 16) + String.fromCharCode(n >>> 0 & 0xffff), block_value(s) = n[6] /[x * 85 + s.charCodeAt(x0 - 1) - 33] -seq, padded = s.length % 5 ? '#{s}uu' : s, decoded_string = n[0, padded.length, 5] *[decode_block(block_value(padded.substr(x, 5)))] -seq -re- it.join
View gist:554455
 function () {var left_in = function (x, ops) {return x.xs && x.xs[0] && (ops[x.xs[0].op] && x.xs[0].op || x.xs[0].xs && x.xs[0].xs[1] && ops[x.xs[0].xs[1].op] && x.xs[0].xs[1].op)}, right_in = function (x, ops) {return x.xs && x.xs[1] && ops[x.xs[1].op] && x.xs[1].op}, \$_ = ''; return '([{'.indexOf(this.op) > -1 ? this.op + s(this.xs[0]) + r.openers[this.op] : this.op == '?' ? s(this.xs[0]) + ' ? ' + s(this.xs[1].xs[0]) + ' : ' + s(this.xs[2]) : this.op == '(!' || this.op == '[!' ? s(this.xs[0]) + s(this.xs[1]) : r.implicit_assignment[this.op] ? '(' + (this.op.char