ssh wrapper to quote command and arguments for remote end

sshsystem

#!/bin/bash

# quote command in ssh call to prevent remote side from expanding any arguments
# uses bash printf %q for quoting - no idea how compatible this is with other shells.
# http://stackoverflow.com/questions/6592376/prevent-ssh-from-breaking-up-shell-script-parameters

sshargs=()

while (( $# > 0 )); do
	case "$1" in
	-[1246AaCfgKkMNnqsTtVvXxYy])
		# simple argument
		sshargs+=("$1")
		shift
		;;
	-[bcDeFIiJLlmOopRSWw])
		# argument with parameter
		sshargs+=("$1")
		shift
		if (( $# == 0 )); then
			echo "missing second part of long argument" >&2
			exit 99
		fi
		sshargs+=("$1")
		shift
		;;
	-[bcDeFIiJLlmOopRSWw]*)
		# argument with parameter appended without space
		sshargs+=("$1")
		shift
		;;
	--)
		# end of arguments
		sshargs+=("$1")
		shift
		break
		;;
	-*)
		echo "unrecognized argument: '$1'" >&2
		exit 99
		;;
	*)
		# end of arguments
		break
		;;
	esac
done


# user@host
sshargs+=("$1")
shift

# command - quote
if (( $# > 0 )); then
	# no need to handle passed command as an array - ssh will merge it anyway.
	# use bash @Q parameter transformation to quote $@:
	sshargs+=("${@@Q}")
fi

exec ssh "${sshargs[@]}"