stevekrenzel

unshred = (shreddedImage, shredWidth) ->
  {width, height} = shreddedImage
  shreds = split shreddedImage, shredWidth

  weights = cross shreds, (x, y) ->
    if x == y
      0
    else
      mean zipWith unzip(rightEdge(x)), unzip(leftEdge(y)), correlate

stevekrenzel

fancyTable = lambda table: '\n'.join("%%%ss " * min(map(len, table)) % tuple(max(map(len, x)) for x in zip(*table)) % tuple(x)[:min(map(len, table))] for x in table)

# You can try it by opening python and running:
# >>> fancyTable = lambda table: '\n'.join("%%%ss " * min(map(len, table)) % tuple(max(map(len, x)) for x in zip(*table)) % tuple(x)[:min(map(len, table))] for x in table)
# >>> print fancyTable([['Text', '1', 'a'], ['Longer Text', '123', 'abc'], ['Even longer text!', '123456789', 'abcdefghi']])
#              Text         1         a 
#       Longer Text       123       abc 
# Even longer text! 123456789 abcdefghi 

stevekrenzel

#include <iostream>
#include <string>
using namespace std;

string findLongestPalindrome(string str) {
  int max_lower = 0, max_upper = 0, len = str.length(), lower = 0, upper = 0;
  for(int i = 0; i < len; i++) {
    upper = i + 1, lower = i;
    for(int j = 0; j < 2; j++) {
      lower = i - j;

stevekrenzel

#include <iostream>
#include <string>
using namespace std;

#define MAX_STR(a, b) (((a.length()) > (b.length())) ? (a) : (b))

string getPalindromeAt(string str, int lower, int upper) {
  for(;lower >= 0 and upper < str.length() and str[lower] == str[upper]
      ;upper++, lower--);
  return str.substr(lower + 1, upper - lower - 1);

stevekrenzel

from collections import defaultdict

def longest_common_substring(a, b):
  index = defaultdict(list)
  for i, c in enumerate(b):
    index[c].append(i)
  mxi, mxj, mxsz = 0, 0, 0
  matches = defaultdict(int)
  for i, c in enumerate(a):
    new_matches = defaultdict(int)