Created
April 29, 2020 17:04
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Simple Python password creator
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from itertools import cycle | |
from random import choice, shuffle | |
from string import ascii_lowercase, ascii_uppercase, digits, punctuation | |
def generate_password(length: int = 20, *, use_symbols: bool = True) -> str: | |
"""Generate random passwords, with or without symbols. | |
Implementation ensures a fairly even balance of each character | |
class, at the cost of entropy (e.g. for a four-character password | |
with symbols there are only 5,191,680 possible combinations, rather | |
than 78,074,896). | |
>>> from random import seed | |
>>> seed(0) | |
>>> generate_password() | |
'm7s;1)j[Yz^Q7G86#JiE' | |
>>> generate_password(use_symbols=True) | |
'o$3k0%M~0H:Q&xRg45Sz' | |
>>> generate_password(use_symbols=False) | |
'o15HGC4sfzpv42Tb9CYM' | |
>>> generate_password(10) | |
'SAc-5h9(Kp' | |
>>> generate_password(10, use_symbols=True) | |
'aDUs%3z8E#' | |
>>> generate_password(10, use_symbols=False) | |
'Ap01v8gGFn' | |
>>> generate_password(0) | |
'' | |
>>> generate_password(-1) | |
'' | |
>>> generate_password("foo") | |
Traceback (most recent call last): | |
... | |
TypeError: 'str' object cannot be interpreted as an integer | |
""" | |
cases = [ascii_lowercase, ascii_uppercase, digits] | |
if use_symbols: | |
cases.append(punctuation) | |
characters = [ | |
choice(case) | |
for _, case | |
in zip(range(length), cycle(cases)) | |
] | |
shuffle(characters) | |
return "".join(characters) | |
if __name__ == "__main__": | |
import doctest | |
doctest.testmod() |
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