Created
February 23, 2016 01:42
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public class BinarytreeisSubTreeOfAnother { | |
//store the inOrder and postorder traversal for both the array, | |
//if one array is the sub array of another array, that means one tree is the subtree of another one | |
public String inOrder(Node root, String i){ | |
if(root!=null){ | |
return inOrder(root.left,i) + " " + root.data + " " +inOrder(root.right,i); | |
} | |
return ""; | |
} | |
public String postOrder(Node root, String i){ | |
if(root!=null){ | |
return postOrder(root.left,i) + " " + postOrder(root.right,i) + " " + root.data; | |
} | |
return ""; | |
} | |
public boolean checkSubtree(Node rootA, Node rootB){ | |
String inOrderA = inOrder(rootA,""); | |
String inOrderB = inOrder(rootB,""); | |
String postOrderA = postOrder(rootA,""); | |
String postOrderB = postOrder(rootB,""); | |
return (inOrderA.toLowerCase().contains(inOrderB.toLowerCase()) && postOrderA.toLowerCase().contains(postOrderB.toLowerCase())); | |
} | |
public void display(Node root){ | |
if(root!=null){ | |
display(root.left); | |
System.out.print(" " + root.data); | |
display(root.right); | |
} | |
} | |
public static void main (String[] args) throws java.lang.Exception | |
{ | |
Node rootA = new Node(1); | |
rootA.left = new Node(2); | |
rootA.right = new Node(4); | |
rootA.left.left = new Node(3); | |
rootA.right.right = new Node(6); | |
rootA.right.left = new Node(5); | |
Node rootB = new Node(4); | |
rootB.left = new Node(5); | |
rootB.right = new Node(6); | |
BinarytreeisSubTreeOfAnother i = new BinarytreeisSubTreeOfAnother(); | |
System.out.print(" Tree A : "); | |
i.display(rootA); | |
System.out.println(); | |
System.out.print(" Tree B : "); | |
i.display(rootB); | |
System.out.println(); | |
System.out.println(i.checkSubtree(rootA,rootB)); | |
} | |
} | |
class Node{ | |
int data; | |
Node left; | |
Node right; | |
public Node(int data){ | |
this.data = data; | |
this.left = null; | |
this.right = null; | |
} | |
} |
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