timothyw

HI

timothyw

#!/bin/bash
# Calculate the storage space used up by all tables in a given MySQL database
# Ben Dowling - www.coderholic.com
database=$1
username=$2
password=$3

if [ ${#database} -eq 0 ]
then
	echo "Usage: $0 <database> [username [password]]"

timothyw

defaults write com.apple.Dock showhidden -bool YES
killall Dock

timothyw

(This is the text of the keynote I gave at Startup Riot 2009. Will update when video becomes available.)

Hi everyone, I’m Chris Wanstrath, and I’m one of the co-founders of GitHub.

GitHub, if you haven’t heard of it, has been described as “Facebook for developers.” Which is great when talking about GitHub as a website, but not so great when describing GitHub as a business. In fact, I think we’re the polar opposite of Facebook as a business: we’re small, never took investment, and actually make money. Some have even called us successful.

Which I’ve always wondered about. Success is very vague, right? Probably even relative. How do you define it?

After thinking for a while I came up with two criteria. The first is profitability. We employ four people full time, one person part time, have thousands of paying customers, and are still growing. In fact, our rate of growth is increasing – which means January was our best month so far, and February is looking pretty damn good.

timothyw

mysql> SET GLOBAL general_log = 1;
Query OK, 0 rows affected (0.00 sec)

mysql> show variables like 'general%';
+------------------+---------------------------------+
| Variable_name    | Value                           |
+------------------+---------------------------------+
| general_log      | ON                              | 
| general_log_file | /usr/log/mysql/mysql.log        | 
+------------------+---------------------------------+

timothyw

def test(n)
  if n <= 0
    return [[]]
  else
    return test(n-1).map do |x| [true] + x end + test(n-1).map do |x| [false] + x end
  end
end

timothyw

Mostly because yacc does not allow it.  It confuses
 lambda { |foo = bar| puts foo }
as
 lambda { |foo = (bar| puts foo) }
and causes syntax error.

timothyw

# Does NOT work
define_method :method_name do |first_arg="default1", second_arg="default2"|
  # ...
end

timothyw

# Does NOT work
define_method :method_name do |first_arg="default1", second_arg="default2|
  # ...
end

timothyw

# Using optional arguments, with a default value for "two"
define_method :method_name do |required, *optional|
  # one, two, = *optional
  one, two, *ignored = *optional
  # two will have a default value
  two ||= "Default value"
  
  # ...
end