tuckcodes

Keybase proof

I hereby claim:

• I am tuckcodes on github.
• I am tuckcodes (https://keybase.io/tuckcodes) on keybase.
• I have a public key ASBkr47X56OI9DmqWoSQhzQXr0iOLV02-hSxo66cyC-fago

To claim this, I am signing this object:

tuckcodes

pragma solidity 0.5.1;

contract DogContract {
    
    struct Dog {
        string name;
        uint age;
        
    }

tuckcodes

// Even or Odd
// Determine even or odd WITHOUT the modulo operator
// My aim is to add or subtract two from the input until I reach 0 or 1
// If it concludes on 0 it is even, and if on 1 it is odd
function determineIfEven(num1) {
    switch (!isNaN(num1)) {
        case (num1 == 0):               // If the input is 0 then even
            console.log(true);          // Output boolean true
            break;
        case (num1 == 1):               // If the input is 1 then not even

tuckcodes

// Triangle Loop
// Just making a triangle kinda thing in the console
let charPound = "#";
for (let index = 0; index < 8; index++) {
    console.log(charPound.repeat(index));  
}

tuckcodes

// Min rebuild
// Rebuild the min function
function smallestNum(...numbersArray) {
    lowestNumber = true;
    numbersArray.forEach(number => {
        if (lowestNumber == true) {
            lowestNumber = number;
        }
        if (lowestNumber > number) {
            lowestNumber = number

tuckcodes

// Bean Counter
// Determine how many matching letters there are in an input string from an input character
function countChar(stringInput, charSelect) {

    stringInput = String(stringInput);
    let letterArray = Array.from(stringInput), count = 0;

    letterArray.forEach(letter => {
        if (letter == charSelect) {
            count++;

tuckcodes

// FizzBuzz
// Good ol'fashioned fizz buzz
// Decided to use a switch statement to mix it up a little
for (let numStart = 0; numStart<100; numStart++) {
    switch (true) {
        case ((numStart>0) && (numStart%3 == 0)):
            console.log("Fizz");
            break;

        case ((numStart>0) && (numStart%5 == 0)):

tuckcodes

// Chess Board
// Create a chess board with a congigurable row amount parameter
let size = prompt(Number("How many rows?")), board = "# # # #";
for (let count = 0; count < size; count++) {
    if (count%2==0) {
        console.log(" " + board)
    } else {
        console.log(board);
        }
}