Android Development for Beginners : Practice Set 2 Email Directory Example

MainActivity.java

        String firstName = "Lyla";
        String lastName = "Fujiwara";
        String contactInfo = firstName + " " + lastName;
        contactInfo = "<" + lastName + "." + firstName + "@justjava.com>";
        display(contactInfo);

Not correct.
it's displaying:
Fujiwara.Lyla@justjava.com

The Result of code

So This Not Correct

The Correct Code To Achieve The Goal Is

  String firstName = "Lyla";
        String lastName = "Fujiwara";
        String contactInfo = firstName + " " + lastName;
        contactInfo = firstName + " " + lastName + "<" + lastName + "." + firstName + "@justjava.com>";
        display(contactInfo);

the code should be:
String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo = firstName + " " + lastName;
contactInfo = contactInfo + ”<“ + lastName + "." + firstName + "@justjava.com>";
display(contactInfo);

What is displayed would be:
Lyla FujiwaraFujiwara.Lyla@justjava.com

@Manoj0718 could you screen the code

only setting part of the needed out put

not correct
String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo = firstName + " " + lastName;
contactInfo = "<" + lastName + "." + firstName + "@justjava.com>";
display(contactInfo);............................................<Fujiwara.Lyla@justjava.com>

to display the correct message the code will be

String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo = firstName + " " + lastName;
contactInfo = contactInfo + "<" + lastName + "." + firstName + "@justjava.com>";
display(contactInfo);

String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo= firstName+" "+lastName;
contactInfo+="<" + lastName+"."+firstName+"@justjava.com>";
display(contactInfo);

String firstName ="Lyla";
String lastName ="Fujiwara";
String contactInfo=firstName+" "+lastName;
contactInfo= contactInfo+"<"+lastName+"."+firstName+"@justjava.com>";
display(contactInfo);

hey everyone, I am getting the same errors as @R964 and @JobVilligran please help @udacityandroid

Given

String firstName = "Lyla";

    String lastName = "Fujiwara";

    String contactInfo = firstName + " " + lastName;

    contactInfo = "<" + lastName + "." + firstName + "@justjava.com>";

    display(contactInfo);

Corrected Code

String firstName = "Lyla ";

    String lastName = "Fujiwara";

    String contactInfo = firstName + " " + lastName;

    contactInfo = " <" + lastName + "." + firstName + "@justjava.com>";

    display(firstName + lastName + contactInfo);

Another option to correct program...

String firstName = "Lyla ";

    String lastName = "Fujiwara";

    String contactInfo = firstName + " " + lastName;

    contactInfo = firstName + lastName + " <" + lastName + "." + firstName + "@justjava.com>";

    display(contactInfo);

Hey i got the
Error :- Stirng cannot be converted to int and i solved this issue so what we have to do is change the value of public void to string value

String firstName = "Lyla"; String lastName = "Fujiwara"; String contactInfo = firstName + " " + lastName; contactInfo = contactInfo + "<" + lastName + "." + firstName + "@justjava.com>"; display1(contactInfo);
// This is the right java code and the programme will run fine .
public void display1(String text) { TextView t = (TextView) findViewById(R.id.display_text_view); t.setText(text); }

Happy to Help

`package com.example.android.practiceset2;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    String firstName = "Lyla";
    String lastName = "Fujiwara";
    String contactInfo = firstName + " " + lastName;
    contactInfo = contactInfo + " <" + lastName + "." + firstName + "@justjava.com>";
    display(contactInfo);
}
/**
 * Display methods that allow the text to appear on the screen. Don't worry if you don't know
 * how these work yet. We'll be covering them in lesson 3.
 */

public void display(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view);
    t.setText(text);
}

public void display(int text) {
    TextView t = (TextView) findViewById(R.id.display_text_view);
    t.setText(text + "");
}

public void display1(String text) {
    display(text);
}

public void display2(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view_2);
    t.setText(text);
}

public void display3(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view_3);
    t.setText(text);
}

}`

The fix is

String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo = firstName + " " + lastName;
contactInfo +="<" + lastName + "." + firstName + "@justjava.com>";
display(contactInfo);

package com.example.android.practiceset2;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    String firstName = "Lyla";
    String lastName = "Fujiwara";
    String conttactInfo = firstName + " " + lastName;
    conttactInfo = "<" + lastName + "." + firstName + "@justjava.com>";
    display(conttactInfo);

}

/**
 * Display methods that allow the text to appear on the screen. Don't worry if you don't know
 * how these work yet. We'll be covering them in lesson 3.
 */
public void display(String i) {
    TextView t = (TextView) findViewById(R.id.display_text_view);
    t.setText(""+ i);
}

}

<TextView
    android:id="@+id/display_text_view"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:textSize="45sp" />

it's displaying:
Fujiwara.Lyla@justjava.com

Fujiwara.Lyla@justjava.com

package com.example.android.practiceset2;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    // PASTE CODE YOU WANT TO TEST HERE

    String firstName = "Lyla";
    String lastName = "Fujiwara";
    String contactInfo = firstName + " " + lastName;
    String contactName = firstName + " " + lastName;
    contactName = (firstName + " " lastName);
    contactInfo = "<" + firstName + "." + lastName + "@justjava.com>";
    display(contactName);
    display2(contactInfo);


}

/**
 * Display methods that allow the text to appear on the screen. Don't worry if you don't know
 * how these work yet. We'll be covering them in lesson 3.
 */

public void display(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view);
    t.setText(text);
}

// public void display(int text) {
// TextView t = (TextView) findViewById(R.id.display_text_view);
// t.setText(text + "");
// }

public void display1(String text) {
    display(text);
}

public void display2(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view_2);
    t.setText(text);
}

public void display3(String text) {
    TextView t = (TextView) findViewById(R.id.display_text_view_3);
    t.setText(text);
}

}

This worked for me...

Fujiwara.Lyla@justjava.com

Correct Code:

String firstName = "Lyla";
String lastName = "Fujiwara";
String contactInfo = firstName + " " + lastName;
contactInfo = contactInfo + "<" + lastName + "." + firstName + "@justjava.com>";
display(contactInfo);

Fujiwara.Lyla@justjava.com

Done!

package com.example.android.practiceset2;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        // PASTE CODE YOU WANT TO TEST HERE

        //  int weekday = 5;
        //  int weekend = 9;
        //  int optimalHours = 7 * 8;

        //  int actualHours = weekday;
        //  actualHours = actualHours + weekend * 2;
        //  int solution = optimalHours - actualHours;
        //  display(solution);

        // int dollars = 40;
        // int dollarsToYen = 119;
        // int yen = dollarsToYen * dollars;
        // display(yen);

        String firstName = "Shiva";
        String lastName = "Shankar";
        String contactInfo = firstName + " " + lastName;
        contactInfo = "<" + lastName + "." + firstName + "@justjava.com>";
        display(contactInfo);

    }

    /**
     * Display methods that allow the text to appear on the screen. Don't worry if you don't know
     * how these work yet. We'll be covering them in lesson 3.
     */

    public void display(String text) {
        TextView t = (TextView) findViewById(R.id.display_text_view);
        t.setText(text);
    }

    public void display(int text) {
        TextView t = (TextView) findViewById(R.id.display_text_view);
        t.setText(text + "");
    }

    public void display1(String text) {
        display(text);
    }

    public void display2(String text) {
        TextView t = (TextView) findViewById(R.id.display_text_view_2);
        t.setText(text);
    }

    public void display3(String text) {
        TextView t = (TextView) findViewById(R.id.display_text_view_3);
        t.setText(text);
    }
}

I can not find the mistake... Please, I will need help

public void display(String i)
so
public void display1(String i) {
TextView t = (TextView) findViewById(R.id.display_text_view);
t.setText(i + "");
}

Maybe
String firstName = "Lyla";
String lastName = "Fujiwara";
String fullName = firstName + " " + lastName;
String contactInfo = "<" + lastName + "." + firstName + "@justjava.com>";
display(fullName + contactInfo);

This worked for me :

    String firstName = "Lyla ";  
    String lastName = "Fujiwara";
    String contactInfo = firstName +  lastName +  " <" + lastName + "." + firstName + "@justjava.com>";
    display(contactInfo);

• I merged the 3rd line with the 4th line and removed the double quotes in the third line
• I also added a space to the string of the first name, to create a space between the first and last name