Created
March 3, 2018 17:23
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刑侦科推理试题程序作答
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#coding=utf-8 | |
import sys | |
reload(sys) | |
sys.setdefaultencoding('utf-8') | |
i=0 | |
option=['o','a','b','c','d'] | |
for a in xrange(1,5): | |
for b in xrange(1,5): | |
for c in xrange(1,5): | |
for d in xrange(1,5): | |
for e in xrange(1,5): | |
for f in xrange(1,5): | |
for g in xrange(1,5): | |
for h in xrange(1,5): | |
for i in xrange(1,5): | |
for j in xrange(1,5): | |
count=[0,0,0,0] | |
count[a-1]+=1 | |
count[b-1]+=1 | |
count[c-1]+=1 | |
count[d-1]+=1 | |
count[e-1]+=1 | |
count[f-1]+=1 | |
count[g-1]+=1 | |
count[h-1]+=1 | |
count[i-1]+=1 | |
count[j-1]+=1 | |
minOption = count.index(min(count))+1 | |
minNum = min(count) | |
maxNum = max(count) | |
if g == minOption : | |
if (maxNum-minNum==3 and j==1) or (maxNum-minNum==2 and j==2) or (maxNum-minNum==4 and j==3 ) or (maxNum-minNum==1 and j==4): | |
if (d==1 and a==e) or (d==2 and b==g) or (d==3 and a==i) or ( d==4 and f==j): | |
if (d==b and d==f and b==f and c==1) or (b==d and c==b and c==d and c==2) or (f==d and c==f and c==d and c==3) or (f==b and c==f and c==b and c==4): | |
if (e==1 and e==h and b==3) or (e==2 and e==d and b==4) or (e==3 and e==i and b==1) or (e==4 and e==g and b==2): | |
if (h==b and h==d and b==d and f==1) or (h==a and h==f and a==f and f==2) or (h==c and h==j and c==j and f==3) or (h==e and h==i and e==i and f==4): | |
if a == f and ((e!=f and i==1) or (e!=j and i==2) or (e!=b and i==3) or (e!=i and i==4)): | |
print(option[a]+','+option[b]+','+option[c]+','+option[d]+','+option[e]+','+option[f]+','+option[g]+','+option[h]+','+option[i]+','+option[j]) | |
elif a != f and ((e==f and i==1) or (e==j and i==2) or (e==b and i==3) or (e==i and i==4)): | |
print(option[a]+','+option[b]+','+option[c]+','+option[d]+','+option[e]+','+option[f]+','+option[g]+','+option[h]+','+option[i]+','+option[j]) | |
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