Scala Concurrent port of https://github.com/twitter/util/blob/master/util-core/src/main/scala/com/twitter/util/Future.scala#L331-336

select.scala

 /**
   * "Select" off the first future to be satisfied.  Return this as a
   * result, with the remainder of the Futures as a sequence.
   *
   * @param fs a scala.collection.Seq
   */
  def select[A](fs: Seq[Future[A]])(implicit ec: ExecutionContext): Future[(Try[A], Seq[Future[A]])] = {
    @tailrec
    def stripe(p: Promise[(Try[A], Seq[Future[A]])],
               heads: Seq[Future[A]],
               elem: Future[A],
               tail: Seq[Future[A]]): Future[(Try[A], Seq[Future[A]])] = {
      elem onComplete { res => if (!p.isCompleted) p.trySuccess((res, heads ++ tail)) }
      if (tail.isEmpty) p.future
      else stripe(p, heads :+ elem, tail.head, tail.tail)
    }

    if (fs.isEmpty) Future.failed(new IllegalArgumentException("empty future list!"))
    else stripe(Promise(), fs.genericBuilder[Future[A]].result, fs.head, fs.tail)
  }

Thanks. I use this code to show how to transform a Seq[Future[X]] into an Enumerator[X]

http://stackoverflow.com/questions/15543261/transforming-a-seqfuturex-into-an-enumeratorx/15545906