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@vznvzn
Created March 5, 2017 03:35
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require 'statsample'
def stat(l)
l = [0] if (l.empty?)
t = t2 = 0
l.each \
{
|x|
t += x
t2 += x ** 2
}
c = l.size
a = t.to_f / c
z = t2.to_f / c - a ** 2
sd = Math.sqrt(z < 0 ? 0 : z)
return a, sd, l.max.to_f
end
def stat2(l, t, n)
return Hash[[["a#{n}", "sd#{n}", "mx#{n}"], stat(l).map { |x| x / t }].transpose]
end
def d(s)
c = s.split('').select { |x| x == '1' }.size
d = c.to_f / s.length
return d
end
def data(x)
n = x['n']
ns = n.to_s(2)
nl = ns.length
m = nl / 2
nsh = ns[0..m]
nsl = ns[m..-1]
asdm1 = stat2(ns.split(/0+/).map { |x| x.length }, nl, 1)
l1 = ns.split(/1+/)
l1.shift
asdm0 = stat2(l1.map { |x| x.length }, nl, 0)
return {'n' => x['n'], 'y' => x['y'], 'd' => d(ns), 'dh' => d(nsh), 'dl' => d(nsl)}.merge(asdm0).merge(asdm1)
end
def f2(n)
n = (n * 3 + 1) / 2 while (n.odd?)
n /= 2 while (n.even?)
return n
end
def adv(n, c)
l = []
c.times \
{
n = f2(n)
l << n
}
return l
end
def fit(l, y, lx)
a = {}
(lx + [y]).each { |x| a[x] = l.map { |b| b[x] }.to_vector() }
ds = a.to_dataset()
r = Statsample::Regression.multiple(ds, y)
$stderr.puts(r.summary)
return r.coeffs.merge({'c' => r.constant})
end
def dot(x, z)
t = z['c']
(z.keys - ['c']).each { |k| t += z[k] * x[k] }
return t
end
def sum(l)
t = 0
l.each { |x| t += x }
return t
end
def av(l)
return nil if (l.empty?)
return sum(l) / l.size
end
def predict(z, l1)
l1.each_with_index \
{
|x, i|
t = dot(x, z)
ns1 = x['n'].to_i.to_s(2).length
t = 100 if (t < 100)
l2 = [t.to_f * ns1]
adv(x['n'].to_i, 10).each \
{
|n|
x2 = data({'n' => n})
ns = n.to_s(2).length
t = dot(x2, z)
t = 100 if (t < 100)
t *= ns.to_f
l2 << t
}
x['y_p'] = av(l2) / ns1
x['y_p'] = 100 if (x['y_p'] < 100)
}
end
def out(fn, l)
f = File.open("#{fn}.txt", 'w')
f.puts(l[0].keys.join("\t"))
l.each { |x| f.puts(x.values.join("\t")) }
f.close
end
def read(fn)
l = File.open('data.txt').readlines
l1 = l.shift.split
return l.map \
{
|x|
Hash[[l1, x.split.map { |y| y.to_f }].transpose]
}
end
l2 = read('data.txt')
$stderr.puts("#{l2.size} pts")
# out('out', l2)
z = fit(l2, 'y', l2[0].keys - ['y', 'n'])
predict(z, l2)
out('out1', l2.sort_by { |x| x['y'] })
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