Order (or sort) one list the same way that a second list is ordered. Orders multiple identical values correctly.

orderLike.py

def orderLike(unordered:list, ordered:list):
  """
  Takes 2 lists where the first list is the unordered list that should be
  ordered similar to the second list which is in the correct order.  This
  solution handles identical values appearing in the ordered list.  Returns a
  new list without modifying the lists that were passed in.
  """
  result = []
  unordered = unordered[:]
  for ordered_value in ordered:
    # Check for non-NaN values
    if ordered_value in unordered:
      unordered.pop(unordered.index(ordered_value))
      result.append(ordered_value)
    # Check for NaN
    elif ordered_value != ordered_value:
      for i, v in enumerate(unordered):
        if v != v:
          unordered.pop(i)
          result.append(v)
          break
  return result + unordered

~example.py

from orderLike import orderLike

unordered = [float('nan'), 4, 5, 2, float('nan')]
ordered = [1, 2, 3, 5, 7, float('nan')]
print(orderLike(unordered, ordered))
# [2, 5, nan, 4, nan]