python: Run specific command on file content line by line

process-file.py2

#
#  Run specific command on file content line by line
#  Coded by Myo Soe
#
#

import sys, getopt, os


def main(argv):
    #print len(argv)
    if len(argv) is not 4:
        print 'process-file.py -i <inputfile> -c os_command_to_run'
        sys.exit()


    inputfile = ''
    command = 'echo '
    try:
        opts, args = getopt.getopt(argv, "hi:c:", ["ifile=", "cmd="])
    except getopt.GetoptError:
        print 'process-file.py -i <inputfile> -c <os_command>'
        sys.exit(2)
    for opt, arg in opts:
        if opt == '-h':
            print 'process-file.py -i <inputfile> -c os_command_to_run'
            sys.exit()
        elif opt in ("-i", "--ifile"):
            inputfile = arg
        elif opt in ("-c", "--cmd"):
            command = arg
    if os.path.exists(inputfile) == False:
        print 'Input file "' + inputfile + '" was not found!'


    #print 'Input file is "', inputfile
    #print 'Command is "', command
    f = open(inputfile)

    for line in iter(f):
        line = line.rstrip()
        r = os.system(command + ' "' + line + '"');
        #print r
    f.close()


if __name__ == "__main__":
    main(sys.argv[1:])