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# zSANSANz/floydWarshall.cpp

Last active Mar 6, 2020
Floyd Warshall Algorithm on C++
 // C Program for Floyd Warshall Algorithm #include // Number of vertices in the graph #define V 4 /* Define Infinite as a large enough value. This value will be used for vertices not connected to each other */ #define INF 99999 // A function to print the solution matrix void printSolution(int dist[][V]); // Solves the all-pairs shortest path problem using Floyd Warshall algorithm void floydWarshall (int graph[][V]) { /* dist[][] will be the output matrix that will finally have the shortest distances between every pair of vertices */ int dist[V][V], i, j, k; /* Initialize the solution matrix same as input graph matrix. Or we can say the initial values of shortest distances are based on shortest paths considering no intermediate vertex. */ for (i = 0; i < V; i++) for (j = 0; j < V; j++) dist[i][j] = graph[i][j]; /* Add all vertices one by one to the set of intermediate vertices. ---> Before start of a iteration, we have shortest distances between all pairs of vertices such that the shortest distances consider only the vertices in set {0, 1, 2, .. k-1} as intermediate vertices. ----> After the end of a iteration, vertex no. k is added to the set of intermediate vertices and the set becomes {0, 1, 2, .. k} */ for (k = 0; k < V; k++) { // Pick all vertices as source one by one for (i = 0; i < V; i++) { // Pick all vertices as destination for the // above picked source for (j = 0; j < V; j++) { // If vertex k is on the shortest path from // i to j, then update the value of dist[i][j] if (dist[i][k] + dist[k][j] < dist[i][j]) dist[i][j] = dist[i][k] + dist[k][j]; } } } // Print the shortest distance matrix printSolution(dist); } /* A utility function to print solution */ void printSolution(int dist[][V]) { printf ("Following matrix shows the shortest distances" " between every pair of vertices \n"); for (int i = 0; i < V; i++) { for (int j = 0; j < V; j++) { if (dist[i][j] == INF) printf("%7s", "INF"); else printf ("%7d", dist[i][j]); } printf("\n"); } } // driver program to test above function int main() { /* Let us create the following weighted graph 10 (0)------->(3) | /|\ 5 | | | | 1 \|/ | (1)------->(2) 3 */ int graph[V][V] = { {0, 5, INF, 10}, {INF, 0, 3, INF}, {INF, INF, 0, 1}, {INF, INF, INF, 0} }; // Print the solution floydWarshall(graph); return 0; }

### Hussain-Safwan commented Sep 2, 2018

 Din't get the point of a direct copy-paste from GeeksForGeeks? Check this out: https://www.geeksforgeeks.org/floyd-warshall-algorithm-dp-16/

### aminPial commented Mar 6, 2020 • edited

 dude, are you trying to just show off someone that you know all of those algorithm by just Copy Pasting from other sources! XD
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