Created
November 10, 2018 05:10
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/** | |
* Definition for singly-linked list. | |
* struct ListNode { | |
* int val; | |
* ListNode *next; | |
* ListNode(int x) : val(x), next(NULL) {} | |
* }; | |
*/ | |
class Solution { | |
public: | |
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2){ | |
ListNode head(0); | |
ListNode* h = &head; | |
while(l1&&l2){ | |
if(l1->val < l2->val){ | |
h->next = l1; | |
h=h->next; | |
l1= l1->next; | |
} | |
else{ | |
h->next = l2; | |
h = h->next; | |
l2=l2->next; | |
} | |
} | |
if(l1) | |
{ | |
h->next = l1; | |
} | |
if(l2) | |
{ | |
h->next = l2; | |
} | |
return head.next; | |
} | |
ListNode* mergeKLists(vector<ListNode*>& lists) { | |
int len_l = lists.size(); | |
if(len_l == 0) | |
return nullptr; | |
int step = 1; | |
while(step < len_l){ | |
for(int i = 0; i + step < len_l; i = i + step*2) | |
{ | |
lists[i] = mergeTwoLists(lists[i], lists[i+step]); | |
} | |
step = step*2; | |
} | |
return lists[0]; | |
} | |
}; |
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