Given a string, look for a mirror image (backwards) string at both the beginning and end of the given string. In other words, zero or more characters at the very begining of the given string, and at the very end of the string in reverse order (possibly overlapping). For example, the string "abXYZba" has the mirror end "ab". mirrorEnds("abXYZba")…

MirrorsEnd.java

package teach;

public class MirrorsEnd {

  /**
   * @param args
	 */
	public static void main(String[] args) {
		String[] words = { "abXYZba", "abca", "aba", "Hi and iH", "123and then 321" };

		for (int i = 0; i < words.length; i++) {			
			System.out.println(words[i] + " => " + mirrorEnds(words[i]));
		}
	}
	
	public static String mirrorEnds(String temp) {
		StringBuilder sb= new StringBuilder("");
		boolean diff	= false;

		for (int i = 0; i < temp.length() / 2 && (!diff); i++) {
			if (temp.charAt(i) == temp.charAt((temp.length() - 1) - i)) {
				sb.append(temp.charAt(i));
			} else {
				diff = true;
			}
		}
		if (!diff)
			sb = new StringBuilder(temp);
		return sb.toString();
	}

}