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Last active December 16, 2015 00:18
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Solve a magic square variant in Matlab
% Program to solve a sort of magic square, where only the rows and columns
% must sum to the magic constant, and not the diagonals. Some elements of
% the square are given in advance while others (indicated with 0) are
% unknown.
%
% TF Time-Wasting Project 04-2013
function result = fu_puzzle
puzzle = ...
[ 1 0 0 0 22
0 24 0 11 0
0 0 5 0 0
0 3 0 17 0
19 0 0 0 13 ];
result = solve_magic(puzzle);
end
function M = magic_constant(n)
M = n*(n^2 + 1)/2;
end
function solvable = is_solvable_helper(puzzle, n, M)
solvable = 0;
% solvable = all( ((~any(puzzle==0)) & (sum(puzzle) == M)) ...
% | (( any(puzzle==0)) & (sum(puzzle) <= M)) );
values = remaining_values(puzzle);
for ii=1:n
row = puzzle(ii, :); % Fetch a row of the puzzle
x = (row==0); % Identify the unknown cells
nx = numel(find(x)); % How many are they?
% If all cells in the row are filled in, then the row MUST sum to the
% correct value.
if (nx == 0) && (sum(row) ~= M)
return
end
% If not all cells are filled in, populate them with the lowest-valued
% remaining possibilities, and ensure that the sum of the row does not
% exceed the magic constant.
row(x) = values(1:nx);
if sum(row) > M
return
end
row(x) = values(end-nx+1:end);
if sum(row) < M
return
end
end
% If we get this far, then we haven't found any problems.
solvable = 1;
end
% Check whether a puzzle may still be solved by filling in more values
function result = is_solvable(puzzle)
n = size(puzzle, 1);
M = magic_constant(n);
result = is_solvable_helper(puzzle, n, M) && ...
is_solvable_helper(puzzle', n, M);
end
% What numbers haven't been used yet?
function values = remaining_values(puzzle)
values = setdiff(1:numel(puzzle), puzzle(:));
end
% Solve the puzzle
function solutions = solve_magic(puzzle)
solutions = {};
if ~is_solvable(puzzle)
return
end
values = remaining_values(puzzle);
if isempty(values)
% No more values to put in --> the problem is solved!
solutions = {puzzle}
return
end
%position = find(puzzle==0, 1, 'first');
% Try to encounter a constraint as soon as possible:
positions = find(puzzle==0);
[rows, cols] = ind2sub(size(puzzle), positions);
col_remaining = sum(puzzle ==0);
row_remaining = sum(puzzle'==0);
remaining = sort([row_remaining(rows); col_remaining(cols)]);
[~, ii] = sortrows(remaining');
position = positions(ii(1));
for value = values,
puzzle(position) = value;
solutions = [solutions solve_magic(puzzle)];
end
end
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