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@ctmakro
Last active February 3, 2019 13:04
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Iterative Trilaterate Algorithm in Python3
import numpy as np
def normalized(v):
norm = np.sqrt(np.sum(v**2))
return v / norm
# Trilateration to find the target point, given positions of 3 points, and distances(radiuses)
def trilaterate(points, distances):
precision = 1e-3
iteration = 1000
# points -> list of numpy vectors
# distances -> list of distances
# t -> initial guess
t = np.array([0,0,-10]).astype('float32')
# v -> initial velocity
v = t*0
for i in range(iteration):
# print('t@',i,t)
total_force = v*0
tick = 0
for idx in range(len(points)):
direction = points[idx] - t # direction vector from t to sphere center
dist_diff = (np.sqrt(np.sum(direction**2)) - distances[idx]) # distance difference
force = dist_diff * normalized(direction)
total_force += force
if abs(dist_diff) < precision:
tick+=1
if tick>=len(points):
break
else:
tick=0
v += total_force # spring
v *= 0.9 # damping
t += v
print('took',i+1,'iteration to solve trilateration')
return t
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ctmakro commented Aug 23, 2017

this algorithm is conceptually and physically simpler than an analytic solution. the same high precision can be achieved, given enough iterations.

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