typescript discriminated union question

gistfile1.txt

interface HomeView {
  view: 'home';
}

export interface BookView {
  view: 'book';
  link: string;
  page: number;
}

interface FindView {
  view: 'find';
  query?: string;
}

interface ChooseView {
  view: 'choose';
  query?: string;
}

interface YourFavoritesView {
  view: 'your-favorites';
}

interface ErrorView {
  view: 'error';
}

interface SettingsView {
  view: 'settings';
}

type View = HomeView | BookView | FindView | ChooseView | YourFavoritesView | ErrorView | SettingsView;

// How can I get the type for View.view without creating this trash variable?

let foo: View;
type ViewName = typeof foo.view;