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traviskaufman/02-03-demystifying-rxjs-sqsum-test-1.ts

Created October 25, 2019 14:03
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Demystifying RxJS, Part II: Sum of Squares with pipe() / operators
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02-03-demystifying-rxjs-sqsum-test-1.ts
const oneThroughTen = of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
oneThroughTen
.pipe(
map(n => n * n),
reduce((s, n) => s + n, 0)
)
.subscribe(sqSum => console.log("Squared sum =", sqSum));
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