get file structure from codebase

get_file_structure

import os

def get_file_structure(root_path, indent=""):
    """
    Generates a string representation of the file and directory structure
    rooted at the given path.

    Args:
        root_path: The path to the root directory.
        indent: The current indentation level (used for recursive calls).

    Returns:
        A string representing the file structure.
    """
    structure = ""
    if os.path.isdir(root_path):
        structure += indent + os.path.basename(root_path) + "/\n"
        for item in os.listdir(root_path):
            item_path = os.path.join(root_path, item)
            structure += get_file_structure(item_path, indent + "│   ")
    else:
        structure += indent + os.path.basename(root_path) + "\n"
    return structure

def main():
    project_root = os.path.dirname(os.path.abspath(__file__))  # Get path of the current script
    file_structure = get_file_structure(project_root)
    print(file_structure)

if __name__ == "__main__":
    main()