Forked from jfollmann/intersection-difference-union.js
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February 5, 2025 03:05
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Array intersection, difference, and union in ES6
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const arrA = [1, 3, 4, 5]; | |
const arrB = [1, 2, 5, 6, 7]; | |
const intersection = arrA.filter((x) => arrB.includes(x)); | |
console.log('intersection', intersection); | |
// Output => intersection [ 1, 5 ] | |
const differenceA = arrA.filter((x) => !arrB.includes(x)); | |
console.log('differenceA', differenceA); | |
// Output => difference [ 3, 4 ] | |
const differenceB = arrB.filter((x) => !arrA.includes(x)); | |
console.log('differenceB', differenceB); | |
// Output => difference [ 2, 6, 7 ] | |
const symmetricalDifference = arrA | |
.filter((x) => !arrB.includes(x)) | |
.concat(arrB.filter((x) => !arrA.includes(x))); | |
console.log('symmetricalDifference', symmetricalDifference); | |
// Output => symmetricalDifference [ 3, 4, 2, 6, 7 ] | |
const union = [...arrA, ...arrB]; | |
console.log('union', union); | |
// Output => union [1, 3, 4, 5, 1,2, 5, 6, 7] | |
const unionWithoutDuplications = [...new Set([...arrA, ...arrB])]; | |
console.log('unionWithoutDuplications', unionWithoutDuplications); | |
// Output => unionWithoutDuplications [1, 3, 4, 5, 2, 6, 7] | |
// Reference https://medium.com/@alvaro.saburido/set-theory-for-arrays-in-es6-eb2f20a61848 |
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