[Django 1.3] django.views.generic.TemplateView example

feed.html

"{{ params.id }}"

urls.py

from django.conf.urls.defaults import *
from django.views import generic
# from <app_name> import views

urlpatterns = patterns('',
    
#     (r'^(?P<id>[a-zA-Z0-9]{32})/$', views.Show.as_view()),
    
    # Example: d0732c86f9b44a428fc30e935ef90fcf
    (r'^(?P<id>[a-zA-Z0-9]{32})/$', generic.TemplateView.as_view(
        template_name='<app_name>/feed.html',
    )),
    
)

views.py

from django.views import generic

"""
class Show(generic.TemplateView):
    
    template_name = 'wire/feed.html'
    
    def get_context_data(self, **kwargs):
        
        return {
            'params': kwargs,
        }
"""

Is there a faster way of doing the above?

Discussion found here.

You could use a plain (not class-based) view function and the render() or render_to_response() shortcut. But that would require only marginally less code.

Thanks for the help eppsilon! I really appreciate it. :)

I definitely don't mind the code above... Basically I just wanted to make sure that I was properly using the "TemplateView", class-based generic view, for something as simple as passing URL param to a template.

I feel pretty comfortable with the old functional view stuff, but for some reason the new class-based views have been giving me trouble. :D

Thanks so much for you help and taking the time to give a helpful answer.

Cheers,
Micky

I posted an update in my urls.py file; I suppose that is one way to skip a view and go directly to template.

Looking at TemplateView class in the Django source code, kwargs is already passed to the template as a variable labeled "params".