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@tatiana
Created June 22, 2012 19:14
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Trying to replace SPARQL query using RDFAlchemy's rdfSubject
from rdfalchemy import rdfSingle, rdfSubject
from rdfalchemy.sparql import SPARQLGraph
from rdflib import Namespace
query = """
PREFIX db: <http://dbpedia.org/resource/>
PREFIX dbprop: <http://dbpedia.org/property/>
PREFIX dbonto: <http://dbpedia.org/ontology/>
SELECT distinct ?name ?label {
?artist
a dbonto:MusicalArtist;
dbprop:birthName ?name.
{
?artist dbonto:instrument db:Guitar .
db:Guitar rdfs:label ?label.
}
UNION
{
?artist dbonto:instrument db:Piano .
db:Piano rdfs:label ?label .
}
FILTER ( lang(?name) = "en" )
}
ORDER BY ?name
LIMIT 10
"""
DB = Namespace('http://dbpedia.org/resource/')
DBPROP = Namespace('http://dbpedia.org/property/')
DBONTO = Namespace('http://dbpedia.org/ontology/')
RDFS = Namespace('http://www.w3.org/2000/01/rdf-schema#')
endpoint = "http://live.dbpedia.org/sparql"
graph = SPARQLGraph(endpoint)
rdfSubject.db = graph
class Instrument(rdfSubject):
rdfs_label = rdfSingle(RDFS.label, 'label')
class MusicalArtist(rdfSubject):
rdf_type = DBONTO.MusicalArtist
dbprop_birthname = DBPROP.birthName
dbonto_instrument = Instrument # ?
guitar_players = MusicalArtist.get_by(dbonto_instrument=DB.Guitar)
# Line above throws "AttributeError: type object 'rdfSubject' has no attribute 'pred'"
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