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オフラインどう書く3回目 Haskellによる解答例
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import Data.Char (ord) | |
import Data.List (elemIndex) | |
type Input = String | |
type Output = String | |
tests :: [(Input, Output)] | |
tests = [ ("b","AB"), | |
("l","AD"), | |
("r","AC"), | |
("bbb","ABAB"), | |
("rrr","ACBA"), | |
("blll","ABCAB"), | |
("llll","ADEBA"), | |
("rbrl","ACADE"), | |
("brrrr","ABEDAB"), | |
("llrrr","ADEFDE"), | |
("lrlll","ADFEDF"), | |
("lrrrr","ADFCAD"), | |
("rllll","ACFDAC"), | |
("blrrrr","ABCFEBC"), | |
("brllll","ABEFCBE"), | |
("bbbrrlrl","ABABEDFCB"), | |
("rbllrrrr","ACABCFEBC"), | |
("lbrlrrblr","ADABCFEFCA"), | |
("rlbrrrrbl","ACFCADFCFD"), | |
("bllrlrbrrb","ABCADEFEBCB"), | |
("rllrllllbb","ACFDEBADEDE"), | |
("blblrlrrlbr","ABCBEDFCABAC"), | |
("lrlrrrrrbrb","ADFEBCFEBEDE"), | |
("rblllrlrrlrr","ACABCADEFDABE"), | |
("rbrrlrblrllb","ACADFEBEFDACA"), | |
("lrrrlrllrrllr","ADFCABEFCADEBC"), | |
("rrlblllrrlrrb","ACBEBADEFDABEB"), | |
("brbllrrbbrlrll","ABEBADFCFCABEFC"), | |
("rrrbbrlbrlblrb","ACBABACFCABADFD"), | |
("lllllllllllblrr","ADEBADEBADEBEFDE"), | |
("llllllrllrlbrrr","ADEBADEFCBADABED")] | |
main = print $ filter (not . snd) $ zip [0..] (map test tests) | |
test (input, output) = solve input == output | |
road :: [(Char, String)] | |
road = [('A', "DCB"), | |
('B', "ACE"), | |
('C', "AFB"), | |
('D', "FAE"), | |
('E', "DBF"), | |
('F', "CDE")] | |
type Action = Char -> Char -> Char | |
solve :: Input -> Output | |
solve = solve' 'B' 'A' . map toAction | |
solve' :: Char -> Char -> [Action] -> Output | |
solve' _ cur [] = [cur] | |
solve' prev cur (action:cs) = cur : solve' cur (action prev cur) cs | |
toAction :: Char -> Action | |
toAction 'b' = turn (+0) | |
toAction 'l' = turn (+1) | |
toAction 'r' = turn (subtract 1) | |
toAction _ = error "toAction" | |
turn :: (Int -> Int) -> Action | |
turn a prev cur = lst !! next | |
where | |
(_, lst) = road !! (ord cur - ord 'A') | |
next = (a (j $ elemIndex prev lst) + len) `mod` len | |
j (Just x) = x | |
j _ = error "lookup" | |
len = length lst |
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