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AOJ0588,Cheese
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#define REP(i,n) for (int i=0;i<(n);i++) | |
#include <queue> | |
#include <iostream> | |
using namespace std; | |
const int MAX = 1000; | |
const int INF = 10000; | |
typedef pair<int,int> P; //座標マクロ | |
int N,M,c_num; | |
int sx,sy; | |
int gx,gy; | |
P C[9]; | |
char field[MAX][MAX+1]; //field | |
int d[MAX][MAX+1]; //distance | |
int dx[4] = {1, 0, -1, 0}; | |
int dy[4] = {0, 1, 0, -1}; | |
void init(){ | |
// cout << "init ..." << endl; | |
REP(i,N){ | |
REP(j,M){ | |
if (! (i == sx && j == sy)) d[i][j] = INF; | |
} | |
} | |
// cout << "start: " << d[sx][sy] << endl; | |
} | |
void bfs(){ | |
init(); | |
queue <P> que; | |
que.push(P(sx,sy)); | |
while(que.size()){ | |
P p = que.front(); que.pop(); | |
if (p.first == gx && p.second == gy) break; | |
// 周辺4マスを調べる | |
for(int r = 0; r < 4; r++) { | |
int nx = p.first + dx[r], ny = p.second + dy[r]; | |
if (0 <= nx && nx < N && 0 <= ny && ny < M && field[nx][ny] != 'X' &&d[nx][ny] == INF){ | |
d[nx][ny] = d[p.first][p.second] + 1; | |
que.push(P(nx,ny)); | |
} | |
} | |
} | |
return ; | |
} | |
void solve(){ | |
REP(i,c_num){ | |
gx = C[i].first, gy = C[i].second; | |
//cout << 'goal :'<< gx << gy << endl; | |
bfs(); | |
sx = gx, sy = gy; | |
} | |
cout << d[gx][gy] << endl; | |
} | |
int main(){ | |
cin >> N >> M >> c_num; | |
REP(i,N){ | |
REP(j,M){ | |
cin >> field[i][j]; | |
if (field[i][j] == 'S') sx = i, sy = j; | |
else if ('1' <= field[i][j] && field[i][j] <= '9'){ | |
C [field[i][j]-'1'] = P(i,j); | |
} | |
} | |
} | |
solve(); | |
} |
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