CryptoPass implementation in Python

cryptopass.py

# Cryptopass by dchest

# Based on:

# pbkdf2.py -- library to calculate keys from passwords
# Copyright (C) 2010 Tobias Ammann

# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License as
# published by the Free Software Foundation; either version 3 of
# the License, or (at your option) any later version.

# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.

# You should have received a copy of the GNU General Public
# License along with this program; if not, see
# <http://www.gnu.org/licenses/>.

from math import ceil
from functools import partial
from hashlib import sha1, sha256
from hmac import new as hmac

def pbkdf2(password, salt, dk_length, iterations=1000,
           hashfunc=sha1):
    digest_size = hashfunc().digest_size
    prf = partial(hmac, digestmod=hashfunc)
    assert dk_length < 2**32 - 1, 'derived key too long'

    l = int(ceil(float(dk_length)/digest_size))

    def xor(a, b):
        return ''.join([chr(ord(x)^ord(y)) for (x, y) in zip(a, b)])

    def i2b(i):
        i = hex(i)[2:]
        i = '0'*(8-len(i)) + i
        return i.decode('hex')

    dk = ''

    for b in xrange(1, l+1):
        u = prf(password, salt + i2b(b)).digest()

Run:

python cryptopass.py

Example:

$ python cryptopass.py "my super secret" tester google.com 25
Juq5MzGrXU7zivT13MHdpXGzq