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201506Q1003
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data work1001; | |
p=cdf('normal',25,20,5); /*正規分布の累積分布関数->CDF*/ | |
z=1-p; /*問では超える確率としているので、正規分布の右側の面積の数値を求める*/ | |
n=7; | |
d0=comb(n,0)*z**0*(1-z)**(n-0); /*0日の確率*/ | |
d1=comb(n,1)*z**1*(1-z)**(n-1); /*1日の確率*/ | |
d2=comb(n,2)*z**2*(1-z)**(n-2); /*2日の確率*/ | |
d3=comb(n,3)*z**3*(1-z)**(n-3); /*3日の確率*/ | |
d4=comb(n,4)*z**4*(1-z)**(n-4); /*4日の確率*/ | |
d5=comb(n,5)*z**5*(1-z)**(n-5); /*5日の確率*/ | |
d6=comb(n,6)*z**6*(1-z)**(n-6); /*6日の確率*/ | |
d7=comb(n,7)*z**7*(1-z)**(n-7); /*7日の確率*/ | |
d8=d6+d7+d5+d4+d3+d2; /*2日以上の確率*/ | |
d9=1-d0-d1; /*2日以上の確率*/ | |
run; | |
proc print data=work1001; | |
run; |
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