Buchberger Christopher CodeChrisB

## emoji.js
[↩,↪,⌚,⌛,⌨,⏏,⏩,⏪,⏫,⏬,⏰,⏱,⏲,⏳,⏹,Ⓜ,▪,▫,▶,◀,◻,◼,◽,◾,☀,☁,☂,☂,☃,☄,☎,☑,☔,☕,☘,☝,☠,☢,☣,☦,☪,☮,☯,☸,☹,☺,♈,♉,♊,♋,♌,♍,♎,♏,♐,♑,♒,♓,♠,♣,♥,♦,♨,♻,♿,⚒,⚓,⚔,⚖,⚗,⚙,⚛,⚠,⚡,⚪,⚫,⚰,⚱,⚽,⚾,⛄,⛅,⛈,⛎,⛏,⛑,⛓,⛔,⛩,⛪,⛰,⛱,⛱,⛲,⛳,⛴,⛵,⛷,⛸,⛹,⛹️‍♀️,⛹️‍♂️,⛺,⛽,✂,✅,✈,✉,✊,✋,✌,✍,✏,✒,✔,✖,✝,✡,✨,✳,✴,❄,❇,❌,❎,❓,❔,❕,❗,❣,❤,➕,➖,➗,➡,➰,➿,⤴,⤵,⬅,⬆,⬇,⬛,⬜,⭐,⭕,〽,㊗,㊙,🀄,🃏,🅰,🅱,🅾,🅿,🆎,🆑,🆒,🆓,🆔,🆕,🆖,🆗,🆘,🆙,🆚,🈁,🈂,🈚,🈯,🈲,🈳,🈴,🈵,🈶,🈷,🈸,🈹,🈺,🉐,🉑,🌀,🌁,🌂,🌃,🌄,🌅,🌆,🌇,🌈,🌉,🌊,🌋,🌌,🌍,🌎,🌏,🌐,🌑,🌒,🌓,🌔,🌕,🌖,🌗,🌘,🌙,🌚,🌛,🌜,🌝,🌞,🌟,🌠,🌠,🌡,🌤,🌥,🌦,🌧,🌨,🌩,🌪,🌫,🌬,🌭,🌮,🌯,🌰,🌰,🌱,🌲,🌳,🌴,🌵,🌶,🌷,🌸,🌹,🌺,🌻,🌼,🌽,🌾,🌿,🍀,🍁,🍂,🍃,🍄,🍄,🍅,🍆,🍇,🍈,🍉,🍊,🍋,🍌,🍍,🍎,🍏,🍐,🍑,🍒,🍓,🍔,🍕,🍖,🍗,🍘,🍙,🍚,🍛,🍜,🍝,🍞,🍟,🍠,🍡,🍢,🍣,🍤,🍥,🍦,🍧,🍨,🍩,🍪,🍫,🍬,🍭,🍮,🍯,🍰,🍱,🍲,🍳,🍴,🍵,🍶,🍷,🍸,🍹,🍺,🍻,🍼,🍽,🍾,🍿,🎀,🎁,🎂,🎄,🎅,🎆,🎇,🎈,🎉,🎊,🎋,🎌,🎍,🎎,🎏,🎐,🎑,🎒,🎓,🎖,🎗,🎙,🎚,🎛,🎞,🎟,🎠,🎡,🎢,🎣,🎤,🎥,🎦,🎧,🎨,🎩,🎪,🎫,🎬,🎭,🎮,🎯,🎰,🎱,🎲,🎳,🎴,🎵,🎶,🎷,🎸,🎹,🎺,🎻,🎼,🎽,🎾,🎿,🏀,🏁,🏂,🏃,🏃‍♀️,🏃‍♂️,🏄,🏄‍♀️,🏄‍♂️,🏅,🏆,🏇,🏈,🏉,🏊,🏊‍♀️,🏊‍♂️,🏋,🏋️‍♀️,🏋️‍♂️,🏌,🏌️‍♀️,🏌️‍♂️,🏍,🏎,🏏,🏐,🏑,🏒,🏓,🏔,🏕,🏖,🏗,🏘,🏙,🏚,🏛,🏜,🏝,🏞,🏟,🏠,🏡,🏢,🏣,🏤,🏥,🏦,🏧,🏨,🏩,🏪,🏫,🏬,🏭,🏮,🏯,🏰,🏳,🏳️‍🌈,🏴,🏴‍☠️,🏴󠁧󠁢󠁥󠁮󠁧󠁿,🏴󠁧󠁢󠁳󠁣󠁴󠁿,🏴󠁧󠁢󠁷󠁬󠁳󠁿,🏵,🏷,🏸,🏹,🏺,🐀,🐁,🐂,🐃,🐄,🐅,🐆,🐇,🐈,🐉,🐊,🐋,🐌,🐍,🐎,🐏,🐐,🐑,🐒,🐓,🐔,🐕,🐖,🐗,🐘,🐙,🐚,🐛,🐜,🐝,🐞,🐟,🐠,🐡,🐢,🐣,🐤,🐥,🐦,🐧

## script-wettbewerb
//Normal solution
/*
Output: ********************* (21 chars)
Changes :
for(i=0; i>n;i--) --> for(i=0; i<=n;i++)

First up we changed the i--, so that the variable
i increases with every step and we changed i<n
to i<=n so that we the condition willbe true for one step more
now the condition will be true for values from 0-20 which are 21 steps.

## Pokétwo Helper
// Code for Dev Console
let x = [...document.getElementsByClassName("originalLink-Azwuo9")].pop() //Get Last Image of Channel
let url = `https://lens.google.com/uploadbyurl?url=${x.href}` //Create Google Lense Url
let w = window.open(url) //Open Google Lense in new Tab

//Code as Bookmark (One Click Execution)
//Just create a bookmark and put in the code below as the url
javascript: (() => {
  window.open(`https://lens.google.com/uploadbyurl?url=${[...document.getElementsByClassName("originalLink-Azwuo9")].pop().href}`)
})();

## test.js
(()=>{var e={192:(e,a,t)=>{"use strict";t.d(a,{Z:()=>r});var n=t(81),o=t.n(n),s=t(645),i=t.n(s)()(o());i.push([e.id,"@import url(https://fonts.googleapis.com/css2?family=Source+Code+Pro:wght@700&display=swap);"]),i.push([e.id,'@keyframes fadeInUpBig{from{transform:translate3d(0, 100%, 0);opacity:0}to{transform:translate3d(0, 0, 0);opacity:1}}@keyframes fadeInUpTiny{from{transform:translate3d(0, 5px, 0);opacity:.7}to{transform:translate3d(0, 0, 0);opacity:1}}@keyframes fadeOut{from{opacity:1}to{opacity:0}}.swal2-popup.swal2-toast{box-sizing:border-box;grid-column:1/4 !important;grid-row:1/4 !important;grid-template-columns:min-content auto min-content;padding:16px 24px;overflow-y:hidden;background:#32373c;box-shadow:0 2px 4px rgba(0,0,0,.3);pointer-events:all}.swal2-popup.swal2-toast>*{grid-column:2}.swal2-popup.swal2-toast .swal2-title{margin:.5em 1em;padding:0;font-size:13px;text-align:initial}.swal2-popup.swal2-toast .swal2-loading{justify-content:center}.swal2-popup.swal2-toast .swal2-input{height:2em;marg
	//Normal solution
	/*
	Output: ********************* (21 chars)
	Changes :
	for(i=0; i>n;i--) --> for(i=0; i<=n;i++)

	First up we changed the i--, so that the variable
	i increases with every step and we changed i<n
	to i<=n so that we the condition willbe true for one step more
	now the condition will be true for values from 0-20 which are 21 steps.
	// Code for Dev Console
	let x = [...document.getElementsByClassName("originalLink-Azwuo9")].pop() //Get Last Image of Channel
	let url = `https://lens.google.com/uploadbyurl?url=${x.href}` //Create Google Lense Url
	let w = window.open(url) //Open Google Lense in new Tab

	//Code as Bookmark (One Click Execution)
	//Just create a bookmark and put in the code below as the url
	javascript: (() => {
	window.open(`https://lens.google.com/uploadbyurl?url=${[...document.getElementsByClassName("originalLink-Azwuo9")].pop().href}`)
	})();