Codehunter-py

def first_and_last(message):
  if not message or message[0] == message[len(message)-1]:
    return True
  else:
    return False

Codehunter-py

def initials(phrase):
    words = phrase.split()
    result = ""
    for word in words:
        result += word[0].upper()
    return result
    

Codehunter-py

def student_grade(name, grade):
	return "{} received {}% on the exam".format(name, grade)

print(student_grade("Reed", 80))
print(student_grade("Paige", 92))
print(student_grade("Jesse", 85))

Codehunter-py

String operations
len(string) Returns the length of the string

for character in string Iterates over each character in the string

if substring in string Checks whether the substring is part of the string

string[i] Accesses the character at index i of the string, starting at zero

string[i:j] Accesses the substring starting at index i, ending at index j-1. 

Codehunter-py

def replace_ending(sentence, old, new):
    # Check if the old string is at the end of the sentence
    if sentence.endswith(old):
        # Using i as the slicing index, combine the part
        # of the sentence up to the matched string at the 
        # end with the new string
        i = len(old)
        new_sentence = sentence[:-i]+new
        return new_sentence
    # Return the original sentence if there is no match

Codehunter-py

def is_palindrome(input_string):
    # We'll create two strings, to compare them
    new_string = ""
    reverse_string = ""
    # Traverse through each letter of the input string
    for letter in input_string.strip():
        # Add any non-blank letters to the 
        # end of one string, and to the front
        # of the other string. 
        new_string = new_string+letter.replace(" ","")

Codehunter-py

def skip_elements(elements):
  # Initialize variables
  new_list = []
  i = 0

  # Iterate through the list by value and not index
  for element in elements:
      # Does this element belong in the resulting list? Check on index
      if i % 2 == 0:
          # Add this element to the resulting list

Codehunter-py

def skip_elements(elements):
	# code goes here
	new_list = []
	for index, element in enumerate(elements): 
		if index % 2 == 0:
			new_list.append(element)

	
	return new_list
    

Codehunter-py

Common sequence operations
len(sequence) Returns the length of the sequence

for element in sequence Iterates over each element in the sequence

if element in sequence Checks whether the element is part of the sequence

sequence[i] Accesses the element at index i of the sequence, starting at zero

Codehunter-py

def group_list(group, users):
  members = [ user for user in users]
  return "{}: {}".format(group, members)

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"