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Keybase proof

I hereby claim:

  • I am hvho on github.
  • I am hvho (https://keybase.io/hvho) on keybase.
  • I have a public key ASDv1YInPIExAf-_ebgd02TD6GTDrv0N53hXlQXeTPoXzQo

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🌞 Morning 4 commits ▍░░░░░░░░░░░░░░░░░░░░ 2.2%
🌆 Daytime 74 commits ████████▍░░░░░░░░░░░░ 40.0%
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export AWS_ACCESS_KEY_ID=${위에서 생성한 ACCESS KEY}
export AWs_SECRET_ACCESS_KEY=${위에서 생성한 SECRET ACCESS KEY}
resource "aws_instance" "example" {
ami = "ami-0ba5cd124d7a79612"
instance_type = "t2.micro"
vpc_security_group_ids = [aws_security_group.instance.id]
user_data = <<-EOF
#!/bin/bash
echo "Hello, World" > index.html
nohup busybox httpd -f -p 8080 &
@Service
class RetryableService {
@Autowired
private lateinit var retryTemplate: RetryTemplate
fun run() : Unit {
retryTemplate.execute<Unit, Throwable> {
action()
}
@Service
class RetryableService {
@Autowired
private lateinit var retryTemplate: RetryTemplate
fun run() : Unit {
retryTemplate.execute<Unit, Throwable> {
action()
}
@Service
class RetryableService {
@Retryable
fun run() : Unit {
action()
}
}
implementation("org.springframework.retry:spring-retry")
implementation("org.springframework:spring-aspects")
@SpringBootApplication
@EnableRetry
class RetryTestApplication
fun main(args: Array<String>) {
// main function
}
@Service
class RetryableService {
@Autowired
private lateinit var retryTemplate: RetryTemplate
@Retryable
fun doWithRetry() : Unit {
randomFail()
}