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@Hoverbear
Last active December 22, 2015 02:18
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{
"metadata": {
"name": "Untitled0"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": "$$ V = \\int_0^{\\sqrt{\\frac{\\pi}{2}}}{2\\pi*4x\\sin{2x^2}}dx $$"
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": "$u$ Subsitution"
},
{
"cell_type": "markdown",
"metadata": {},
"source": "Let:\n$$ u = x^2, du=2xdx $$"
},
{
"cell_type": "markdown",
"metadata": {},
"source": "$$ V = \\int_{0}^{\\sqrt{\\frac{\\pi}{2}}}{2\\pi\\sin({2(x^2)})2(2xdx)} = \\int_{0}^{\\sqrt{\\frac{\\pi}{2}}}{2\\pi\\sin{(2(u))}2(du)} $$"
},
{
"cell_type": "markdown",
"metadata": {},
"source": "Pull out constants:\n$$ V = 4\\pi \\int_{0}^{\\sqrt{\\frac{\\pi}{2}}}{sin{(2u)}du} $$"
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": "Integration of $u$"
},
{
"cell_type": "markdown",
"metadata": {},
"source": ""
}
],
"metadata": {}
}
]
}
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